Hemoglobin contains 0.34 % of iron by mass. The number of Fe atoms in 3.3 g of hemoglobin is: (Given: Atomic mass of Fe is 56 u , N A in 6.022 × 1023 mol -1 )

Question

Hemoglobin contains 0.34 % of iron by mass. The number of Fe atoms in 3.3 g of hemoglobin is: (Given: Atomic mass of Fe is 56 u , N A in 6.022 × 1023 mol -1 ) (A) 1.21 × 105 (B) 12.0 × 1016 (C) 1.21 × 1020 (D) 3.4 × 1022

Tardigrade Admin · Accepted Answer

No. of Fe atoms =(0.34/100) × (3.3/56) × 6.022 × 1023 =1.206 × 1020

Q. Hemoglobin contains $0.34%$ of iron by mass. The number of $F e$ atoms in $3.3 g$ of hemoglobin is : (Given : Atomic mass of $F e$ is $56 u, N_{A}$ in $6.022 \times 1 0^{23} m o l^{- 1}$ )

$1.21 \times 1 0^{5}$

$12.0 \times 1 0^{16}$

$1.21 \times 1 0^{20}$

$3.4 \times 1 0^{22}$

No. of Fe atoms $= \frac{0.34}{100} \times \frac{3.3}{56} \times 6.022 \times 1 0^{23}$
$= 1.206 \times 1 0^{20}$

Q. Hemoglobin contains 0.34% of iron by mass. The number of Fe atoms in 3.3g of hemoglobin is : (Given : Atomic mass of Fe is 56u,NA​ in 6.022×1023mol−1 )

1.21×105

12.0×1016

1.21×1020

3.4×1022