Heisenberg's uncertainty principle can be explained as

Question

Heisenberg's uncertainty principle can be explained as (A)  Δ x ge (Δ p× h/4π )  (B)  Δ x× Δ p ge (h/4π )  (C)  Δ x× Δ p ge (h/π )  (D)  Δ p ge (π h/Δ x)

Tardigrade Admin · Accepted Answer

Heisenberg's uncertainty principle: It is not possible to determine precisely both the position and the momentum (or velocity) of a small moving particle (eg, electron, proton etc) Δ x.Δ p ge (h/4π ) where Δ x,Δ p are the uncertainties with regard to position, momentum respectively.

Q. Heisenberg's uncertainty principle can be explained as

$Δ x \geq \frac{Δ p \times h}{4 π}$

$Δ x \times Δ p \geq \frac{h}{4 π}$

$Δ x \times Δ p \geq \frac{h}{π}$

$Δ p \geq \frac{πh}{Δ x}$

Q. Heisenberg's uncertainty principle can be explained as

Δx≥4πΔp×h​

Δx×Δp≥4πh​

Δx×Δp≥πh​

Δp≥Δxπh​

Heisenberg's uncertainty principle: It is not possible to determine precisely both the position and the momentum (or velocity) of a small moving particle (eg, electron, proton etc) Δx.Δp≥4πh​ where Δx,Δp are the uncertainties with regard to position, momentum respectively.

$Δ x \geq \frac{Δ p \times h}{4 π}$

$Δ x \times Δ p \geq \frac{h}{4 π}$

$Δ x \times Δ p \geq \frac{h}{π}$

$Δ p \geq \frac{πh}{Δ x}$