HCl is produced in the stomach which can be neutralised by Mg(OH)2 in the form of milk of magnesia. How much Mg(OH)2 is required to neutralise one mole of stomach acid?

Question

HCl is produced in the stomach which can be neutralised by Mg(OH)2 in the form of milk of magnesia. How much Mg(OH)2 is required to neutralise one mole of stomach acid? (A) 29.16 g (B) 34.3 g (C) 58.33 g (D) 68.66 g

Tardigrade Admin · Accepted Answer

Mg (OH)2 + 2HCl → MgCl2 +2H2O No. of moles of Mg(OH)2 required for 2 moles of HCl = 1 No. of moles of Mg(OH)2 required for 1 mole of HCl = 0.5 Mass of 0.5 mol of Mg(OH)2 = 58.33 × 0.5 = 29.16 g

Q. $H Cl$ is produced in the stomach which can be neutralised by $M g (O H)_{2}$ in the form of milk of magnesia. How much $M g (O H)_{2}$ is required to neutralise one mole of stomach acid?

$29.16 g$

$34.3 g$

$58.33 g$

$68.66 g$

$M g (O H)_{2} + 2 H Cl \to M g C l_{2} + 2 H_{2} O$
No. of moles of $M g (O H)_{2}$ required for $2$ moles of $H Cl = 1$
No. of moles of $M g (O H)_{2}$ required for $1$ mole of $H Cl = 0.5$
Mass of $0.5 m o l$ of $M g (O H)_{2} = 58.33 \times 0.5 = 29.16 g$

Q. HCl is produced in the stomach which can be neutralised by Mg(OH)2​ in the form of milk of magnesia. How much Mg(OH)2​ is required to neutralise one mole of stomach acid?

29.16g

34.3g

58.33g

68.66g