Hardness of water is 200 ppm. Calculate the molarity and normality of CaCO 3 of the water

Question

Hardness of water is 200 ppm. Calculate the molarity and normality of CaCO 3 of the water (A) 4 × 10-3 M ; 2 × 10-3 N (B) 2 × 10-6 M ; 4 × 10-3 N (C) 2 × 10-3 M ; 4 × 10-3 N (D) 1 × 10-3 M ; 4 × 10-3 N

Tardigrade Admin · Accepted Answer

200 ppm mean 200 g in 106 mL solution Molarity =(w t/M ⋅ w) × (1000/V mL )=(200/100) × (1000/106) =2 × 10-3 M Normality =(200/50) × (1000/106) =4 × 10-3 N

Q. Hardness of water is $200 pp m .$ Calculate the molarity and normality of $C a C O_{3}$ of the water

$4 \times 1 0^{- 3} M; 2 \times 1 0^{- 3} N$

$2 \times 1 0^{- 6} M; 4 \times 1 0^{- 3} N$

$2 \times 1 0^{- 3} M; 4 \times 1 0^{- 3} N$

$1 \times 1 0^{- 3} M; 4 \times 1 0^{- 3} N$

$200 pp m$ mean $200 g$ in $1 0^{6} m L$ solution

Molarity $= \frac{wt}{M \cdot w} \times \frac{1000}{V _{m L}} = \frac{200}{100} \times \frac{1000}{1 0 ^{6}}$

$= 2 \times 1 0^{- 3} M$

Normality $= \frac{200}{50} \times \frac{1000}{1 0 ^{6}}$

$= 4 \times 1 0^{- 3} N$

Q. Hardness of water is 200ppm. Calculate the molarity and normality of CaCO3​ of the water

4×10−3M;2×10−3N

2×10−6M;4×10−3N

2×10−3M;4×10−3N

1×10−3M;4×10−3N