Haemoglobin contains 0.3465 % of iron. One molecule of haemoglobin contains 4 atoms of iron. The molecular mass of haemoglobin is kg mol -1. (Atomic mass: Fe =55.8 u )

Question

Haemoglobin contains 0.3465 % of iron. One molecule of haemoglobin contains 4 atoms of iron. The molecular mass of haemoglobin is kg mol -1. (Atomic mass: Fe =55.8 u ) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

There are four atoms of iron in a molecule of haemoglobin.
Four atoms of iron contribute

0.3465%

mass to a molecule of haemoglobin.
Mass of

4 F e = 55.8 \times 4 = 223.2 u = 0.3465%

Hence,

\frac{223.2}{x} \times 100 = 0.3465

∴ x = \frac{223.2}{0.3465} \times 100 = 64416 g m o l^{- 1}

= 64.42 k g m o l^{- 1}

Q. Haemoglobin contains 0.3465% of iron. One molecule of haemoglobin contains 4 atoms of iron. The molecular mass of haemoglobin is_______ kgmol−1. (Atomic mass: Fe=55.8u )

There are four atoms of iron in a molecule of haemoglobin. Four atoms of iron contribute 0.3465% mass to a molecule of haemoglobin. Mass of 4Fe=55.8×4=223.2u=0.3465% Hence, x223.2​×100=0.3465 ∴x=0.3465223.2​×100=64416gmol−1 =64.42kgmol−1

Q. Haemoglobin contains $0.3465%$ of iron. One molecule of haemoglobin contains $4$ atoms of iron. The molecular mass of haemoglobin is_______ $k g m o l^{- 1}$ . (Atomic mass: $F e = 55.8 u$ )