H3A is a weak tripotic acid (Ka1 = (10)- 6 ; Ka2 = (10)- 10 ; Ka3 = (10)- 14) Calculate the value of (.pY-pX.) of 1(MH)3A(.aq.) solution where X=([HA2 -]/[H2 A-])Y=([A3 -]/[HA2 -])

Question

H3A is a weak tripotic acid (Ka1 = (10)- 6 ; Ka2 = (10)- 10 ; Ka3 = (10)- 14) Calculate the value of (.pY-pX.) of 1(MH)3A(.aq.) solution where X=([HA2 -]/[H2 A-])Y=([A3 -]/[HA2 -]) (A) 10 (B) 3 (C) 7 (D) 4

Tardigrade Admin · Accepted Answer

[H+]=10- 3 Ka2=([H+] [HA2 -]/[H2 A-])Ka3=([H+] [A3 -]/[HA2 -])

Q. $H_{3} A$ is $a$ weak tripotic acid $(K_{a_{1}} = (10)^{- 6}; K_{a_{2}} = (10)^{- 10}; K_{a_{3}} = (10)^{- 14})$
Calculate the value of $(p Y - pX)$ of $1 (M H)_{3} A (a q)$ solution where $X = \frac{[ H A ^{2 -} ]}{[ H _{2} A ^{-} ]} Y = \frac{[ A ^{3 -} ]}{[ H A ^{2 -} ]}$

$10$

$3$

$7$

$4$

$[H^{+}] = 1 0^{- 3}$
$K_{a_{2}} = \frac{[ H ^{+} ] [ H A ^{2 -} ]}{[ H _{2} A ^{-} ]} K_{a_{3}} = \frac{[ H ^{+} ] [ A ^{3 -} ]}{[ H A ^{2 -} ]}$

Q. H3​A is a weak tripotic acid (Ka1​​=(10)−6;Ka2​​=(10)−10;Ka3​​=(10)−14) Calculate the value of (pY−pX) of 1(MH)3​A(aq) solution where X=[H2​A−][HA2−]​Y=[HA2−][A3−]​

10

3

7

4

[H+]=10−3 Ka2​​=[H2​A−][H+][HA2−]​Ka3​​=[HA2−][H+][A3−]​

Q. $H_{3} A$ is $a$ weak tripotic acid $(K_{a_{1}} = (10)^{- 6}; K_{a_{2}} = (10)^{- 10}; K_{a_{3}} = (10)^{- 14})$
Calculate the value of $(p Y - pX)$ of $1 (M H)_{3} A (a q)$ solution where $X = \frac{[ H A ^{2 -} ]}{[ H _{2} A ^{-} ]} Y = \frac{[ A ^{3 -} ]}{[ H A ^{2 -} ]}$

$10$

$3$

$7$

$4$

$[H^{+}] = 1 0^{- 3}$
$K_{a_{2}} = \frac{[ H ^{+} ] [ H A ^{2 -} ]}{[ H _{2} A ^{-} ]} K_{a_{3}} = \frac{[ H ^{+} ] [ A ^{3 -} ]}{[ H A ^{2 -} ]}$