H2Se has higher boiling point than H2S . This is best explained by

Question

H2Se has higher boiling point than H2S . This is best explained by (A) Higher extent of hydrogen bonding in H2Se (B) Higher polarity of H2S (C) Higher polarity of H2Se (D) Higher dispersion forces in H2Se due to its higher molecular weight.

Tardigrade Admin · Accepted Answer

Both H2Se and H2S are polar but the former has higher dispersion forces due to its higher molecular weight and hence the higher boiling point.

Q. $H_{2} S e$ has higher boiling point than $H_{2} S$ . This is best explained by

Higher extent of hydrogen bonding in $H_{2} S e$

Higher polarity of $H_{2} S$

Higher polarity of $H_{2} S e$

Higher dispersion forces in $H_{2} S e$ due to its higher molecular weight.

Both $H_{2} S e$ and $H_{2} S$ are polar but the former has higher dispersion forces due to its higher molecular weight and hence the higher boiling point.

Q. H2​Se has higher boiling point than H2​S . This is best explained by

Higher extent of hydrogen bonding in H2​Se

Higher polarity of H2​S

Higher polarity of H2​Se

Higher dispersion forces in H2​Se due to its higher molecular weight.