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Question
Chemistry
H2O2 reduces K4Fe(CN)6
Q.
H
2
O
2
reduces
K
4
F
e
(
CN
)
6
1988
221
Redox Reactions
Report Error
A
In neutral solution
B
In acidic solution
C
In non-polar solvent
D
In alkaline solution
Solution:
When
H
2
O
2
reduces with
K
4
[
F
e
(
CN
)
6
]
It is present in acidic solution
2
K
4
[
F
e
(
CN
)
6
+
H
2
S
O
4
+
H
2
O
2
→
2
K
3
[
F
e
(
CN
)
6
]
+
K
2
S
O
4
+
2
H
2
O