H 2 O 2 oxidizes MnO 2 to MnO 4-in basic medium. H 2 O 2 and MnO 2 react in the molar ratio of

Question

H 2 O 2 oxidizes MnO 2 to MnO 4-in basic medium. H 2 O 2 and MnO 2 react in the molar ratio of (A) 1:1 (B) 2: 1 (C) 2: 3 (D) 3: 2

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/598df72d172de783afef2afc6137d475-.png" /> Balancing of O.N. 3 H 2 O 2+2 MnO 2 arrow MnO 4-+6 H 2 O Thus, H 2 O 2: MnO 2=3: 2

Q. $H_{2} O_{2}$ oxidizes $M n O_{2}$ to $M n O_{4}^{-}$ in basic medium. $H_{2} O_{2}$ and $M n O_{2}$ react in the molar ratio of

1:1

$2 : 1$

$2 : 3$

$3 : 2$

Balancing of O.N.
$3 H_{2} O_{2} + 2 M n O_{2} \to M n O_{4}^{-} + 6 H_{2} O$
Thus, $H_{2} O_{2} : M n O_{2} = 3 : 2$

Q. H2​O2​ oxidizes MnO2​ to MnO4−​in basic medium. H2​O2​ and MnO2​ react in the molar ratio of

1:1

2:1

2:3

3:2

Balancing of O.N. 3H2​O2​+2MnO2​→MnO4−​+6H2​O Thus, H2​O2​:MnO2​=3:2

Q. $H_{2} O_{2}$ oxidizes $M n O_{2}$ to $M n O_{4}^{-}$ in basic medium. $H_{2} O_{2}$ and $M n O_{2}$ react in the molar ratio of

$2 : 1$

$2 : 3$

$3 : 2$

Balancing of O.N.
$3 H_{2} O_{2} + 2 M n O_{2} \to M n O_{4}^{-} + 6 H_{2} O$
Thus, $H_{2} O_{2} : M n O_{2} = 3 : 2$