Question

$H_2{O}_2$ can not be synthesized by

• A. Addition of ice cold $H_{2}S{O}_4$ on $Ba{O}_2$
• B. Addition of ice cold $H_{2}S{O}_4$ and $Pb{O}_2$
• C. Aerial oxidation of 2 ethyl anthraquinol
• D. Electrolysis of ${\left(N{H}_4\right)}_{2}S{O}_4$ at a high current density

Answer 1

Answer: (B)

(i) $Ba{O}_2(s)+H_{2}S{O}_4(aq)\to BaS{O}_4(s)\downarrow +H_2{O}_2$ (aq)
(ii) $Pb{O}_2+2H_{2}S{O}_4\to Pb\left(S{O}_4\right)+2H_{2}O$
$Pb{O}_2+2H_{2}S{O}_4\stackrel{\Delta }{\to }2PbS{O}_4+O_2+2H_{2}O$
Aerial oxidation of 2-ethylanthraquinol produces 2-ethyl anthraquinone and hydrogen peroxide.
$\to$ Electrolysis of $\to {\left(N{H}_4\right)}_{2}S{O}_4$
(at cathode:- $H^{+}$and $N{H}_4^{+}$ions attracted
$\to N{H}_4^{+}\to N{H}_{3(g)}+\stackrel{\oplus }{H}$ (At Cathode : $2H^{+}+2e^{-}\to H_2$ )
At anode $O{H}^{-}+S{O}_4^{-2}$ ions get attracted
(Net oxidation: $4O{H}^{-}\to O_2+H_2{O}_2+4e^{-}$)