Green light of wavelength 5460 mathringA is incident on an air glass interface. If the refractive index of glass is 1.5, the wavelength of light in glass would be ( c =3 × 108 ms -1)

Question

Green light of wavelength 5460 mathringA is incident on an air glass interface. If the refractive index of glass is 1.5, the wavelength of light in glass would be ( c =3 × 108 ms -1) (A) 3640 mathringA (B) 5460 mathringA (C) 4861 mathringA (D) None of the above

Tardigrade Admin · Accepted Answer

a λ g =(λ a /μ)=(5460/1.5)=3640 mathringA

Q. Green light of wavelength $5460 \overset{˚}{A}$ is incident on an air glass interface. If the refractive index of glass is $1.5$ , the wavelength of light in glass would be $(c = 3 \times 1 0^{8} m s^{- 1})$

$3640 \overset{˚}{A}$

$5460 \overset{˚}{A}$

$4861 \overset{˚}{A}$

None of the above

$a^{λ} g = \frac{λ _{a}}{μ} = \frac{5460}{1.5} = 3640 \overset{˚}{A}$

Q. Green light of wavelength 5460A˚ is incident on an air glass interface. If the refractive index of glass is 1.5, the wavelength of light in glass would be (c=3×108ms−1)

3640A˚

5460A˚

4861A˚