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Tardigrade
Question
Mathematics
Given the sequence of number a1, a2, a3, ldots ldots ldots . . ., a1005 which satisfy (a1/a1+1)=(a2/a2+3)=(a3/a3+5)= ldots ldots . . . . .=(a1005/a1005+2009) Also a1+a2+a3+ ldots ldots+a1005=2010 Nature of the sequence is -
Q. Given the sequence of number
a
1
,
a
2
,
a
3
,
………
...
,
a
1005
which satisfy
a
1
+
1
a
1
=
a
2
+
3
a
2
=
a
3
+
5
a
3
=
……
.....
=
a
1005
+
2009
a
1005
Also
a
1
+
a
2
+
a
3
+
……
+
a
1005
=
2010
Nature of the sequence is -
117
109
Sequences and Series
Report Error
A
A.P.
31%
B
G.P.
3%
C
A.G.P.
54%
D
H.P.
13%
Solution:
Correct answer is (a) A.P.