Given that the surface tension of water is 75 dyne/cm, its density 1 g/cc and angle of contact zero, the height to which water rises in a capillary tube of 1 mm diameter is: (take g=10 text m/s2 )

Question

Given that the surface tension of water is 75 dyne/cm, its density 1 g/cc and angle of contact zero, the height to which water rises in a capillary tube of 1 mm diameter is: (take g=10 text m/s2 ) (A) 9.0 cm (B) 7.5 cm (C) 6.0 cm (D) 3.0cm

Tardigrade Admin · Accepted Answer

Height to which water rises in the capillary tube is h=(2T cos θ /rρ g) Given, T=75 text dyne/cm, text θ =0° , text r=(1/2)× 10 text cm. g=10 text m/s2, text ρ =1 text g/cc. ∴ h=(2× 75× cos 0° × 2/10× 10)=3cm

Q. Given that the surface tension of water is 75 dyne/cm, its density 1 g/cc and angle of contact zero, the height to which water rises in a capillary tube of 1 mm diameter is: (take $g = 10 m / s^{2}$ )

9.0 cm

7.5 cm

6.0 cm

3.0cm

1.5 cm

Height to which water rises in the capillary tube is $h = \frac{2 T c o s θ}{r ρ g}$ Given, $T = 75 d y n e / c m, θ = 0^{\circ}, r = \frac{1}{2} \times 10 c m .$ $g = 10 m / s^{2}, ρ = 1 g / cc .$ $∴$ $h = \frac{2 \times 75 \times c o s 0 ^{\circ} \times 2}{10 \times 10} = 3 c m$

Q. Given that the surface tension of water is 75 dyne/cm, its density 1 g/cc and angle of contact zero, the height to which water rises in a capillary tube of 1 mm diameter is: (take g=10m/s2 )