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Tardigrade
Question
Chemistry
Given standard electrode potentials: Fe3+ + 3e- → Fe; Eo = -0.036 volt Fe2+ + 2e- → Fe; Eo = -0.440 volt The standard electrode potential Eo for Fe3+ + e- → Fe2+
Q. Given standard electrode potentials:
F
e
3
+
+
3
e
−
→
F
e
;
E
o
=
−
0.036
volt
F
e
2
+
+
2
e
−
→
F
e
;
E
o
=
−
0.440
volt
The standard electrode potential
E
o
for
F
e
3
+
+
e
−
→
F
e
2
+
9574
220
Electrochemistry
Report Error
A
−
0.476
volt
0%
B
−
0.404
volt
50%
C
0.440
volt
17%
D
0.772
volt
33%
Solution:
F
e
3
+
+
3
e
→
F
e
,
E
o
,
=
−
0.036
volt;
Δ
G
1
o
F
e
→
F
e
2
+
+
2
e
−
,
E
2
o
=
0.44
volt;
Δ
G
2
o
F
e
3
+
+
e
−
→
Δ
G
o
=
Δ
G
1
o
+
Δ
G
2
o
−
n
F
E
o
=
−
3
F
E
1
o
+
(
−
2
F
E
2
o
)
⇒
−
F
E
o
=
−
F
(
3
E
1
o
+
2
E
2
o
)
E
o
=
(
3
×
(
0.036
)
+
(
2
×
0.44
)
E
o
=
0.772
volt