Given, E I 2 / I -°(1 M )=+0.54 V, and E Br 2 / Br -°(1 M )=1.09 V On this basis the feasible reaction is

Question

Given, E I 2 / I -°(1 M )=+0.54 V, and E Br 2 / Br -°(1 M )=1.09 V On this basis the feasible reaction is (A) 2 Br -+ I 2 longrightarrow Br 2+2 I - (B) I 2+ Br 2 longrightarrow 2 I -+2 Br - (C) 2 I -+ Br 2 longrightarrow I 2+2 Br - (D) 2 I -+2 Br - longrightarrow I 2+ Br 2

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/37229253b31ebd5eeac503c8d3480b97-.png" /> E text cell °=1.09-0.54=+0.55 V Positive E text cell ° means reaction is feasible.

Q. Given, $E_{I_{2} / I^{-}}^{\circ} (1 M) = + 0.54 V$ , and $E_{B r_{2} / B r^{-}}^{\circ} (1 M) = 1.09 V$
On this basis the feasible reaction is

$2 B r^{-} + I_{2} ⟶ B r_{2} + 2 I^{-}$

$I_{2} + B r_{2} ⟶ 2 I^{-} + 2 B r^{-}$

$2 I^{-} + B r_{2} ⟶ I_{2} + 2 B r^{-}$

$2 I^{-} + 2 B r^{-} ⟶ I_{2} + B r_{2}$

$E_{cell}^{\circ} = 1.09 - 0.54 = + 0.55 V$
Positive $E_{cell}^{\circ}$ means reaction is feasible.

Q. Given, EI2​/I−∘​(1M)=+0.54V, and EBr2​/Br−∘​(1M)=1.09V On this basis the feasible reaction is

2Br−+I2​⟶Br2​+2I−

I2​+Br2​⟶2I−+2Br−

2I−+Br2​⟶I2​+2Br−

2I−+2Br−⟶I2​+Br2​