Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R Assertion A: Body 'P' having mass M moving with speed 'u' has head-on collision elastically with another body 'Q' having mass 'm' initially at rest. If m

Question

Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R Assertion A: Body 'P' having mass M moving with speed 'u' has head-on collision elastically with another body 'Q' having mass 'm' initially at rest. If m<< M, body 'Q' will have a maximum speed equal to '2u' after collision Reason R: During elastic collision, the momentum and kinetic energy are both conservedIn the light of the above statements, choose the most appropriate answer from the options given below : (A) A is not correct but R is correct. (B) Both A and R are correct but R is NOT the correct explanation of A (C) Both A and R are correct and R is the correct explanation of A (D) A is correct but R is not correct.

Tardigrade Admin · Accepted Answer

For e =1 second body at rest V 2=(2 m 1 u 1/ m 1+ m 2)=(2 u ( M )/ M + m ) ≃ 2 u Since M gg m

$A$ is not correct but $R$ is correct.

Both $A$ and $R$ are correct but $R$ is NOT the correct explanation of $A$

Both $A$ and $R$ are correct and $R$ is the correct explanation of $A$

$A$ is correct but $R$ is not correct.

For e $= 1$ & second body at rest
$V_{2} = \frac{2 m _{1} u _{1}}{m _{1} + m _{2}} = \frac{2 u ( M )}{M + m} ≃ 2 u$
Since $M ≫ m$

A is not correct but R is correct.

Both A and R are correct but R is NOT the correct explanation of A

Both A and R are correct and R is the correct explanation of A

A is correct but R is not correct.

For e =1 & second body at rest V2​=m1​+m2​2m1​u1​​=M+m2u(M)​≃2u Since M≫m

$A$ is not correct but $R$ is correct.

Both $A$ and $R$ are correct but $R$ is NOT the correct explanation of $A$

Both $A$ and $R$ are correct and $R$ is the correct explanation of $A$

$A$ is correct but $R$ is not correct.

For e $= 1$ & second body at rest
$V_{2} = \frac{2 m _{1} u _{1}}{m _{1} + m _{2}} = \frac{2 u ( M )}{M + m} ≃ 2 u$
Since $M ≫ m$