Q. From the top of a tower a stone is thrown up and reaches the ground in time = 9s. A second stone is thrown down with the same speed and reaches the ground in time = 4s. A third stone is released from rest and reaches the ground in time , which is equal to

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Solution:

Taking downward motion of the first stone from A to ground, we have
.....(i)
Taking downward motion of second stone from A to ground, we have
....(ii)
Third stone
.....(iii)
Multiplying Eq. (i) by and Eq. (ii) by and adding, we get

.......(iv)
From Eqs. (iii) and (iv),
or