From the following graph of photo current against collector plate potential, for two different intensities of light I1 and I2 , one can conclude

Question

From the following graph of photo current against collector plate potential, for two different intensities of light I1 and I2 , one can conclude (A) I1 = I2 (B) I1 > I2 (C) I1 < I2 (D) Comparison is not possible

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The value of photo current depends on the intensity of incident light. Hence, when the intensity of incident light increases, then the value of photo current is increases. i.e. intensity of light (I) propto photo current <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/792b13ac35a16f8a1ac24981c9536686-.png" /> From graph I1 < I2

Q. From the following graph of photo current against collector plate potential, for two different intensities of light $I_{1}$ and $I_{2}$ , one can conclude

$I_{1} = I_{2}$

$I_{1} > I_{2}$

$I_{1} < I_{2}$

Comparison is not possible

The value of photo current depends on the intensity of incident light. Hence, when the intensity of incident light increases, then the value of photo current is increases. i.e.
intensity of light $(I) \propto$ photo current

From graph
$I_{1} < I_{2}$

Q. From the following graph of photo current against collector plate potential, for two different intensities of light I1​ and I2​ , one can conclude

I1​=I2​

I1​>I2​

I1​<I2​