Question

From elementary molecular orbital theory, we can. deduce the electronic configuration of the singly positive nitrogen molecular ion $N_2^{+}$ as

• A. $\sigma 1s^2,{\sigma }^{\ast }1s^2,\sigma 2s^2,{\sigma }^{\ast }2s^2,\pi 2p^4,\sigma 2p^1$
• B. $\sigma 1s^2,{\sigma }^{\ast }1s^2,\sigma 2s^2,{\sigma }^{\ast }2s^2,\sigma 2p^1,\sigma 2p^3$
• C. $\sigma 1s^2,{\sigma }^{\ast }1s^2,\sigma 2s^2,{\sigma }^{\ast }2s^2,\sigma 2p^2,\sigma 2p^4$
• D. $\sigma 1s^2,{\sigma }^{\ast }1s^2,\sigma 2s^2,{\sigma }^{\ast }2s^2,{\sigma }^{\ast }2p^2,\sigma 2p_x^1,\sigma 2p_y^2$
• E. $\sigma 1s^2,{\sigma }^{\ast }1s^2,\sigma 2s^2,{\sigma }^{\ast }2s^2,{\sigma }^{\ast }2p^2,\pi 2p_x^2,\pi 2p_y^2,\sigma 2p_z^1$

Answer 1

Answer: (E)

$N_2^{+}$ ion is formed by the removal of one electron from $N_2$ molecule. The electronic configuration of $N_2^{+}$ ion eill be as: $N_2^{+}:\sigma 1s^2,{\sigma }^{\ast }1s^2,\sigma 2s^2,{\sigma }^{\ast }2s^2,\pi 2p_x^2,\approx \pi 2p_y^2,\sigma 2p_z^1$