From text200 textmg of CO2,1021 molecules are removed. How many molecules are left?

Question

From text200 textmg of CO2,1021 molecules are removed. How many molecules are left? (A) 2.73 (B) 17.3× 1021 (C) 1.73× 1021 (D) None

Tardigrade Admin · Accepted Answer

Molecular weight of CO2=44, Weight = 200 mg = 0.2 g Number of molecules =(w t ./m o l . w t .)× NA =(0.2/44)× 6.023× 1023 =2.73× 1021 The number of molecules left after the removal of 1021 molecules =2.73× 1021-1021 =1.73× 1021 molecules.

Q. From $200 mg$ of $C O_{2}, 1 0^{21}$ molecules are removed. How many molecules are left?

2.73

$17.3 \times 1 0^{21}$

$1.73 \times 1 0^{21}$

None

Q. From 200mg of CO2​,1021 molecules are removed. How many molecules are left?

2.73

17.3×1021

1.73×1021

None

Molecular weight of CO2​=44, Weight = 200 mg = 0.2 g Number of molecules =mol.wt.wt.​×NA​ =440.2​×6.023×1023 =2.73×1021 The number of molecules left after the removal of 1021 molecules =2.73×1021−1021 =1.73×1021 molecules.

Q. From $200 mg$ of $C O_{2}, 1 0^{21}$ molecules are removed. How many molecules are left?

$17.3 \times 1 0^{21}$

$1.73 \times 1 0^{21}$