Four charges q 1=2 × 10-8 C , q 2=-2 × 10-8 C , q 3=-3 × 10-8 C, and q 4=6 × 10-8 C are placed at four corners of a square of side √2 m. What is the potential at the centre of the square?

Question

Four charges q 1=2 × 10-8 C , q 2=-2 × 10-8 C , q 3=-3 × 10-8 C, and q 4=6 × 10-8 C are placed at four corners of a square of side √2 m. What is the potential at the centre of the square? (A) 270 V (B) 300 V (C) Zero (D) 100 V

Tardigrade Admin · Accepted Answer

AC = BD =√(√2)2+(√2)2=2 m <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/0791ad9f551a067c6dc17c5880e4f65b-.png" /> ∴ DO = OB = AO = OC =(2/2)=1 m ∴ Potential at the centre O , V = k ( q / r ) V=k[(2 × 10-8/1)+(-2 × 10-8/1)+(-3 × 10-8/1)+(6 × 10-8/1)] V = k × 3 × 10-8=9 × 109 × 3 × 10-8 volt =27 × 10=270 V

Q. Four charges $q_{1} = 2 \times 1 0^{- 8} C, q_{2} = - 2 \times 1 0^{- 8} C, q_{3} = - 3 \times 1 0^{- 8} C$ , and $q_{4} = 6 \times 1 0^{- 8} C$ are placed at four corners of a square of side $2 m$ . What is the potential at the centre of the square?

$270 V$

$300 V$

Zero

$100 V$

Q. Four charges q1​=2×10−8C,q2​=−2×10−8C,q3​=−3×10−8C, and q4​=6×10−8C are placed at four corners of a square of side 2​m. What is the potential at the centre of the square?

270V

300V

Zero

100V

AC=BD=(2​)2+(2​)2​=2m ∴DO=OB=AO=OC=22​=1m ∴ Potential at the centre O,V=krq​ V=k[12×10−8​+1−2×10−8​+1−3×10−8​+16×10−8​] V=k×3×10−8=9×109×3×10−8 volt =27×10=270V

Q. Four charges $q_{1} = 2 \times 1 0^{- 8} C, q_{2} = - 2 \times 1 0^{- 8} C, q_{3} = - 3 \times 1 0^{- 8} C$ , and $q_{4} = 6 \times 1 0^{- 8} C$ are placed at four corners of a square of side $2 m$ . What is the potential at the centre of the square?

$270 V$

$300 V$

$100 V$