Q.
Four charges 10−5−2×108;+3×108 and 2×10−8 Coulomb are -placed at the four corners of a square,of side 1m the potential at the center of the square is
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Electrostatic Potential and Capacitance
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Solution:
Potential at centre =(21)2k(10−8)+(21)k(−2×10−8)+(21)k(2×10−8)+(21)k(3×10−8) =k2(10−8+3×10−8) =4×10−8×9×109×2 =3602 volts