For the reaction, N2O4 (g)leftharpoons2(NO)2 (g) triangle U=2.1kCal, triangle S=20CalK- 1 at300K , then triangle G is at 300K is...

Question

For the reaction, N2O4 (g)leftharpoons2(NO)2 (g) triangle U=2.1kCal, triangle S=20CalK- 1 at300K , then triangle G is at 300K is... (A) +9.3kCal (B) -9.3kCal (C) -3.3kCal (D) +3.3kCal

Tardigrade Admin · Accepted Answer

triangle H= triangle U+ triangle ngRT =2.1+(1 × 2 × 300/1000) =2.1+0.6 =2.7KCal ∴ triangle G= triangle H-T triangle S =2.7-(300 × 20/1000) =2.7-6 =-3.3KCal

Q. For the reaction, $N_{2} O_{4 (g)} ⇌ 2 (NO)_{2 (g)} △ U = 2.1 k C a l,$ $△ S = 20 C a l K^{- 1}$ $a t 300 K$ , then $△ G$ is at $300 K$ is...

$+ 9.3 k C a l$

$- 9.3 k C a l$

$- 3.3 k C a l$

$+ 3.3 k C a l$

$△ H = △ U + △ n_{g} RT$
$= 2.1 + \frac{1 \times 2 \times 300}{1000}$
$= 2.1 + 0.6$
$= 2.7 K C a l$
$∴ △ G = △ H - T △ S$
$= 2.7 - \frac{300 \times 20}{1000}$
$= 2.7 - 6$
$= - 3.3 K C a l$

Q. For the reaction, N2​O4(g)​⇌2(NO)2(g)​△U=2.1kCal, △S=20CalK−1 at300K , then △G is at 300K is...

+9.3kCal

−9.3kCal

−3.3kCal

+3.3kCal