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Tardigrade
Question
Chemistry
For the reaction, N 2( g )+ O 2( g ) leftharpoons 2 NO ( g ) Equilibrium constant K c =2 Degree of association is
Q. For the reaction,
N
2
(
g
)
+
O
2
(
g
)
⇌
2
NO
(
g
)
Equilibrium constant
K
c
=
2
Degree of association is
3210
182
Equilibrium
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A
1
−
2
1
B
1
+
2
1
C
1
+
2
2
D
1
−
2
2
Solution:
Degree of association
=
Number of moles taken
Number of moles associated
∴
K
c
=
(
1
−
x
)
2
(
2
x
)
2
=
2
or,
1
−
x
2
x
=
2
or,
2
x
=
2
−
2
x
or,
x
(
2
+
2
)
=
2
⇒
x
=
2
+
2
2
=
1
+
2
1