For the reaction: H2+I2 xrightarrow[]2HI, the differential rate law is:

Question

For the reaction: H2+I2 xrightarrow[]2HI, the differential rate law is: (A)  -(d[H2]/dt)=-(d[I2]/dt)=2(d[HI[/dt)  (B)  -2(d[H2]/dt)=-2(d[I2]/dt)=(d[HI]/dt)  (C)  -(d[H2]/dt)=-(d[I2]/dt)=(d[HI]/dt)  (D)  -(d[H2]/2dt)=-(d[I2]/2dt)=(d[HI]/dt)

Tardigrade Admin · Accepted Answer

Correct answer is (b) -2(d[H2]/dt)=-2(d[I2]/dt)=(d[HI]/dt)

Q. For the reaction: $H_{2} + I_{2} 2 H I,$ the differential rate law is:

$- \frac{d [ H _{2} ]}{d t} = - \frac{d [ I _{2} ]}{d t} = 2 \frac{d [ H I [}{d t}$

$- 2 \frac{d [ H _{2} ]}{d t} = - 2 \frac{d [ I _{2} ]}{d t} = \frac{d [ H I ]}{d t}$

$- \frac{d [ H _{2} ]}{d t} = - \frac{d [ I _{2} ]}{d t} = \frac{d [ H I ]}{d t}$

$- \frac{d [ H _{2} ]}{2 d t} = - \frac{d [ I _{2} ]}{2 d t} = \frac{d [ H I ]}{d t}$

Correct answer is (b) $- 2 \frac{d [ H _{2} ]}{d t} = - 2 \frac{d [ I _{2} ]}{d t} = \frac{d [ H I ]}{d t}$

Q. For the reaction: H2​+I2​​2HI, the differential rate law is:

−dtd[H2​]​=−dtd[I2​]​=2dtd[HI[​

−2dtd[H2​]​=−2dtd[I2​]​=dtd[HI]​

−dtd[H2​]​=−dtd[I2​]​=dtd[HI]​