For the reaction H2(g)+Br2(g)→2HBr(g) the experimental data suggested that r=k[H2][Br2]1/2 The molecularity and order of the reaction are respectively:

Question

For the reaction H2(g)+Br2(g)→2HBr(g) the experimental data suggested that r=k[H2][Br2]1/2 The molecularity and order of the reaction are respectively: (A) 2, 3/2 (B) 3/2, 3/2 (C) Not defined, 3/2 (D) 1,1/2

Tardigrade Admin · Accepted Answer

H2(g)+Br2(g)→2HBr(g) r=k[H2][Br2]1/2 Molecularity → not defined. (∵ complete reaction) order =1+(1/2)=(3/2)

Q. For the reaction $H_{2} (g) + B r_{2} (g) \to 2 H B r (g)$ the experimental data suggested that $r = k [H_{2}] [B r_{2}]^{1/2}$ The molecularity and order of the reaction are respectively:

$2, 3/2$

$3/2, 3/2$

Not defined, $3/2$

$1, 1/2$

$H_{2} (g) + B r_{2} (g) \to 2 H B r (g)$
$r = k [H_{2}] [B r_{2}] 1/2$
Molecularity $\to$ not defined. $(∵ co m pl e t e re a c t i o n)$
order $= 1 + \frac{1}{2} = \frac{3}{2}$

Q. For the reaction H2​(g)+Br2​(g)→2HBr(g) the experimental data suggested that r=k[H2​][Br2​]1/2 The molecularity and order of the reaction are respectively:

2,3/2

3/2,3/2

Not defined, 3/2

1,1/2