For the reaction: Fe 2 N ( s )+(3/2) H 2( g ) leftharpoons 2 Fe ( s )+ NH 3( g )

Question

For the reaction: Fe 2 N ( s )+(3/2) H 2( g ) leftharpoons 2 Fe ( s )+ NH 3( g ) (A) K C = K P ( RT ) (B) K C = K P ( RT )-1 / 2 (C) K C = K p ( RT )-3 / 2 (D) K C = K P ( RT )1 / 2

Tardigrade Admin · Accepted Answer

For reaction Fe 2 N ( s )+(3/2) H 2( g ) leftharpoons 2 Fe ( s )+ NH 3( g ) Δ ng =(1-(3/2))=-(1/2) K p = K C ( RT )-1 / 2 K C = K p ( RT )1 / 2

Q. For the reaction :
$F e_{2} N (s) + \frac{3}{2} H_{2} (g) ⇌ 2 F e (s) + N H_{3} (g)$

$K_{C} = K_{P} (RT)$

$K_{C} = K_{P} (RT)^{- 1/2}$

$K_{C} = K_{p} (RT)^{- 3/2}$

$K_{C} = K_{P} (RT)^{1/2}$

For reaction

$F e_{2} N (s) + \frac{3}{2} H_{2} (g) ⇌ 2 F e (s) + N H_{3} (g)$

$Δ n g = (1 - \frac{3}{2}) = - \frac{1}{2}$

$K_{p} = K_{C} (RT)^{- 1/2}$

$K_{C} = K_{p} (RT)^{1/2}$

Q. For the reaction : Fe2​N(s)+23​H2​(g)⇌2Fe(s)+NH3​(g)

KC​=KP​(RT)

KC​=KP​(RT)−1/2

KC​=Kp​(RT)−3/2

KC​=KP​(RT)1/2