For the reaction, 2N2O5 → 4NO2 + O2 rate and rate constant are 1.02 × 10-4 mol L-1 s-1 and 3.4 × 10-5 s-1 respectively. The concentration of N2O5 in mol L-1 will be

Question

For the reaction, 2N2O5 → 4NO2 + O2 rate and rate constant are 1.02 × 10-4 mol L-1 s-1 and 3.4 × 10-5 s-1 respectively. The concentration of N2O5 in mol L-1 will be (A) 3.4 × 10-4 (B) 3.0 (C) 5.2 (D) 3.2 × 10-5

Tardigrade Admin · Accepted Answer

[N2O5]=(Rate/k)=(1.02×10-4mol L-1 s-1/3.4×10-5 s-1) =3 mol L-1

Q. For the reaction, $2 N_{2} O_{5} \to 4 N O_{2} + O_{2}$ rate and rate constant are $1.02 \times 1 0^{- 4} m o l L^{- 1} s^{- 1}$ and $3.4 \times 1 0^{- 5} s^{- 1}$ respectively. The concentration of $N_{2} O_{5}$ in mol $L^{- 1}$ will be

$3.4 \times 1 0^{- 4}$

$3.0$

$5.2$

$3.2 \times 1 0^{- 5}$

$[N_{2} O_{5}] = \frac{R a t e}{k} = \frac{1.02 \times 1 0 ^{- 4} m o l L ^{- 1} s ^{- 1}}{3.4 \times 1 0 ^{- 5} s ^{- 1}}$
$= 3 m o l L^{- 1}$

Q. For the reaction, 2N2​O5​→4NO2​+O2​ rate and rate constant are 1.02×10−4molL−1s−1 and 3.4×10−5s−1 respectively. The concentration of N2​O5​ in mol L−1 will be

3.4×10−4

3.0

5.2

3.2×10−5