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Tardigrade
Question
Chemistry
For the process A(1,0.05 atm , 32° C ) arrow A (g, 0.05 atm , 32° C ) The correct set of thermodynamic parameters is
Q. For the process
A
(
1
,
0.05
a
t
m
,
3
2
∘
C
)
→
A
(
g
,
0.05
a
t
m
,
3
2
∘
C
)
The correct set of thermodynamic parameters is
2300
197
KEAM
KEAM 2017
Thermodynamics
Report Error
A
Δ
G
=
0
and
S
Δ
=
−
v
e
14%
B
Δ
G
=
0
and
S
Δ
=
+
v
e
69%
C
Δ
G
=
+
v
e
and
S
Δ
=
0
8%
D
Δ
G
=
−
v
e
and
S
Δ
=
0
4%
E
Δ
G
=
0
and
S
Δ
=
0
4%
Solution:
(i)
∵
n
and
T
are constant.
∴
Δ
G
=
0
i.e.
System is equilibrium
(ii)
∵
P
→
decreases
∴
Δ
S
→
increases i.e.
(
+
)
v
e
∴
Correct answer is
→
(
B
)