Question

For the given circuit the current $i$ through the battery when the key in closed and the steady state has been reached is______

• A. 6 A
• B. 25 A
• C. 10 A
• D. 0 A

Answer 1

Answer: (C)

In steady state, inductor behaves as a conducting wire.
So, equivalent circuit becomes

$\frac{1}{R_{\text{eq }}}=\frac{1}{3}+\frac{1}{3}+\frac{1}{3}=1$
$\Rightarrow R_{\text{eq }}=1\Omega$
$\Rightarrow$ Circuit becomes

$\Rightarrow i=\frac{30}{3}=10A$