Q.
For the gaseous elementary reaction, A+2BKC;K=10−4bar−2sec−1 If initial partial pressure of A and B are 500 bar and 1 bar respectively, then find time in second to get the partial pressure of B to be 0.1 bar. Assume (50020.1≈500).
rate =10−4PAPB2
rate =10−4×500×PB2
rate =5×10−2PB2
or −21dtdPB=5×10−2PB2
or −dtdPB=10−1PB2
For 2nd order, PB1=PB01+kt
or 0.11=11+0.1×t
or 10=1+0.1t
or t=90sec.