Question

For the fuel cell reaction,
$2H_2+O_2\to 2H_{2}O$
$\Delta G=-475kJ,$ Hence, $E_{cell}^o$ is

• A. 1.23 V
• B. 2.46 V
• C. 0.615 V
• D. 0.31 V

Answer 1

Answer: (A)

$2H_2+O_2\to 2H_{2}O$
Total electrons involved = 4
$\Delta G{}^{\circ }=-nFE{}^{\circ }$
$-475\times 1000=-4\times 96500E{}^{\circ }$
$E{}^{\circ }=1.23V$