Question

For the following molecules :
$PC{l}_5,Br{F}_3,IC{l}_2^{-},Xe{F}_5^{-},N{O}_3^{-},Xe{O}_2{F}_2,PC{l}_4^{+},C{H}_3^{+}$ Calculate the value of $\frac{a+b}{c}$
a = Number of species having $s{p}^{3}d$-hybridisation
b = Number of species which are planar
c = Number of species which are non-planar

Answer 1

Answer: 3

$PC{l}_5\to s{p}^{3}d$, non-planar
$Br{F}_3\to s{p}^{3}d$, bent, $T$-shape, planar
$IC{l}_2^{-}\to s{p}^{3}d$, linear, planar
$Xe{F}_5^{-}\to s{p}^3{d}^3$, pentagonal planar
$N{O}_3^{-}\to s{p}^2$, planar
$Xe{O}_2{F}_2\to s{p}^{3}d$, see-saw, non-planar
$PC{l}_4^{+}\to s{p}^3$, tetrahedral, non-planar
$C{H}_3^{+}\to s{p}^2$, Trigonal planar
$a=4,b=5,c=3$
So, $\frac{a+b}{c}=3$