For the circuit given below, the Kirchoff's loop rule for the loop BCDEB is given by the equation

Question

For the circuit given below, the Kirchoff's loop rule for the loop BCDEB is given by the equation <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/5c4cf60965e68a24d65facaf36b75c6f-.png" /> (A) -i2R2 + E2 - E3 + i3R1 = 0 (B) i2R2 + E2 - E3 - i3R1 = 0 (C) i2R2 + E2 + E3 + i3R1 = 0 (D) - i2R2 + E2 + E3 + i3R1 = 0

Tardigrade Admin · Accepted Answer

By KVL -I2R2-E2+E3+I3R1=0 or I2R2+E2-E3-I3R1=0

Q. For the circuit given below, the Kirchoff's loop rule for the loop $BC D EB$ is given by the equation

$- i_{2} R_{2} + E_{2} - E_{3} + i_{3} R_{1} = 0$

$i_{2} R_{2} + E_{2} - E_{3} - i_{3} R_{1} = 0$

$i_{2} R_{2} + E_{2} + E_{3} + i_{3} R_{1} = 0$

$- i_{2} R_{2} + E_{2} + E_{3} + i_{3} R_{1} = 0$

By $K V L$
$- I_{2} R_{2} - E_{2} + E_{3} + I_{3} R_{1} = 0$
or
$I_{2} R_{2} + E_{2} - E_{3} - I_{3} R_{1} = 0$

Q. For the circuit given below, the Kirchoff's loop rule for the loop BCDEB is given by the equation

−i2​R2​+E2​−E3​+i3​R1​=0

i2​R2​+E2​−E3​−i3​R1​=0

i2​R2​+E2​+E3​+i3​R1​=0

−i2​R2​+E2​+E3​+i3​R1​=0