Question

For same mass of two different ideal gases of molecular weights $M_1$ and $M_2$, plots of $\log Vvs\log P$ at a given constant temperature are shown. Identify the correct option

• A. $M_1>M_2$
• B. $M_1=M_2$
• C. $M_1<M_2$
• D. Can be predicted only if temperature is known

Answer 1

Answer: (A)

For ideal gas, $\log \frac{k}{M_2},\log \frac{k}{M_1}$

$\because pV=\frac{W}{M}RT...(i)$
Let, $WRT=K$
Taking log of both the sides of Eq. (i)
$\log p+\log V=\log \frac{K}{M}$
or $\log V=-\log p+\log \frac{K}{M}...(ii)$
[On compairing Eq. (ii) with $y=mx+C$ ]
$\log \frac{K}{M_2}>\log \frac{K}{M_1}$ or $M_1>M_2$