For reaction RX + OH- → ROH + X-, rate expression is R = 4.7 × 10-5 [RX][OH-]+2.4×10-5[RX] What % of reactant react by SN2 mechanism when [OH-]=0.001 molar?

Question

For reaction RX + OH- → ROH + X-, rate expression is R = 4.7 × 10-5 [RX][OH-]+2.4×10-5[RX] What % of reactant react by SN2 mechanism when [OH-]=0.001 molar? (A) 1.9 (B) 66.2 (C) 95.1 (D) 16.4

Tardigrade Admin · Accepted Answer

Fraction of reactant decomposing by SN2 mechanism =(4.7×10-5[RX][OH-]/4.7×10-5[RX][OH-]+2.4×10-5[RX]) Put [OH-]=0.001 M

Q. For reaction $RX + O H^{-} \to RO H + X^{-},$ rate expression is $R = 4.7 \times 1 0^{- 5} [RX] [O H^{-}] + 2.4 \times 1 0^{- 5} [RX]$ What % of reactant react by $S_{N} 2$ mechanism when $[O H^{-}] = 0.001$ molar?

$1.9$

$66.2$

$95.1$

$16.4$

Fraction of reactant decomposing by $S_{N} 2$ mechanism
$= \frac{4.7 \times 1 0 ^{- 5} [ RX ] [ O H ^{-} ]}{4.7 \times 1 0 ^{- 5} [ RX ] [ O H ^{-} ] + 2.4 \times 1 0 ^{- 5} [ RX ]}$
Put $[O H -] = 0.001 M$

Q. For reaction RX+OH−→ROH+X−, rate expression is R=4.7×10−5[RX][OH−]+2.4×10−5[RX] What % of reactant react by SN​2 mechanism when [OH−]=0.001 molar?

1.9

66.2

95.1

16.4