For P-V diagram of a thermodynamic cycle as shown in figure, process B C and D A are isothermal. Which of the corresponding graphs is correct?

Question

For P-V diagram of a thermodynamic cycle as shown in figure, process B C and D A are isothermal. Which of the corresponding graphs is correct? (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/d76be72e4058ba67299955049f07d31f-.png" /> From A longrightarrow B, volume increasing, pressure constant B longrightarrow C, Pressure propto (1/ text Volume ) ⇒ Temperature constant Same for D longrightarrow A C longrightarrow D pressure decreasing, volume constant So P propto T

Q. For $P - V$ diagram of a thermodynamic cycle as shown in figure, process $BC$ and $D A$ are isothermal. Which of the corresponding graphs is correct?

From $A ⟶ B$ , volume increasing, pressure constant
$B ⟶ C$ , Pressure $\propto \frac{1}{Volume}$
$\Rightarrow$ Temperature constant
Same for $D ⟶ A$
$C ⟶ D$ pressure decreasing, volume constant
So $P \propto T$

Q. For P−V diagram of a thermodynamic cycle as shown in figure, process BC and DA are isothermal. Which of the corresponding graphs is correct?

From A⟶B, volume increasing, pressure constant B⟶C, Pressure ∝ Volume 1​ ⇒ Temperature constant Same for D⟶A C⟶D pressure decreasing, volume constant So P∝T

Q. For $P - V$ diagram of a thermodynamic cycle as shown in figure, process $BC$ and $D A$ are isothermal. Which of the corresponding graphs is correct?

From $A ⟶ B$ , volume increasing, pressure constant
$B ⟶ C$ , Pressure $\propto \frac{1}{Volume}$
$\Rightarrow$ Temperature constant
Same for $D ⟶ A$
$C ⟶ D$ pressure decreasing, volume constant
So $P \propto T$