For n ∈ N, let Pn=∫ limits1e( ln x)n d x, then (P10-90 P8) is equal to

Question

For n ∈ N, let Pn=∫ limits1e( ln x)n d x, then (P10-90 P8) is equal to (A) 10 e (B) -9 e (C) -9 (D) 10

Tardigrade Admin · Accepted Answer

P n =∫ limits1 c underset text (I) ( ln x ) n underset text (II) 1 ⋅ dx ⇒ P n = e - n P n -1

Q. For $n \in N$ , let $P_{n} = 1 \int e (ln x)^{n} d x$ , then $(P_{10} - 90 P_{8})$ is equal to