For light beam of wavelength 632.8 nm, what is the momentum of each photon in the beam?

Question

For light beam of wavelength 632.8 nm, what is the momentum of each photon in the beam? (A) 1.05 × 10-27 kg m s -1 (B) 1.25 × 10-27 kg m s-1 (C) 1.35 × 10-27 kg m s -1 (D) 1.65 × 10-27 kg m s -1

Tardigrade Admin · Accepted Answer

p =(h/λ)=(6.63 × 10-34 Js /632.8 × 10-9 m ) =1.05 × 10-27 kg m s -1

Q. For light beam of wavelength $632.8 nm$ , what is the momentum of each photon in the beam?

$1.05 \times 1 0^{- 27} k g m s^{- 1}$

$1.25 \times 1 0^{- 27} k g m s^{- 1}$

$1.35 \times 1 0^{- 27} k g m s^{- 1}$

$1.65 \times 1 0^{- 27} k g m s^{- 1}$

$p = \frac{h}{λ} = \frac{6.63 \times 1 0 ^{- 34} J s}{632.8 \times 1 0 ^{- 9} m}$
$= 1.05 \times 1 0^{- 27} k g m s^{- 1}$

Q. For light beam of wavelength 632.8nm, what is the momentum of each photon in the beam?

1.05×10−27kgms−1

1.25×10−27kgms−1

1.35×10−27kgms−1

1.65×10−27kgms−1