Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
For hydrogen-oxygen fuel cell, the cell reaction is: 2 H 2( g )+ O 2( g ) arrow 2 H 2 O ( l ) If Δ G f o ( H 2 O )=-237.2 kJ mol -1, then emf of this cell is:
Q. For hydrogen-oxygen fuel cell, the cell reaction is:
2
H
2
(
g
)
+
O
2
(
g
)
→
2
H
2
O
(
l
)
If
Δ
G
f
o
(
H
2
O
)
=
−
237.2
k
J
m
o
l
−
1
, then emf of this cell is:
3630
198
VITEEE
VITEEE 2016
Report Error
A
+ 2.46 V
5%
B
- 2.46 V
15%
C
+ 1.23 V
64%
D
- 1.23 V
15%
Solution:
Gibbs free energy,
Δ
G
∘
=
−
n
F
E
∘
∴
E
∘
=
n
F
Δ
G
∘
=
2
×
96500
237.2
×
1000
J
=
1.23
V
[
∵
n
=
2
]