For Daniell cell, Zn(.s.)+Cu2 +(.aq.)leftharpoons Cu(.s.)+Zn2 +(.aq.) The reaction quotient Q is given by Q=([. Z n2 + ]./[. C u2 + ].) OA = 1.10 volt Where Ec e l l=1.1591 volt, then

Question

For Daniell cell, Zn(.s.)+Cu2 +(.aq.)leftharpoons Cu(.s.)+Zn2 +(.aq.) The reaction quotient Q is given by Q=([. Z n2 + ]./[. C u2 + ].) <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/c-wwkj7di1hh59.png" /> OA = 1.10 volt Where Ec e l l=1.1591 volt, then (A) Q = 0.01 (B) Q = 100 (C) Q = 0.1 (D) Q = 1

Tardigrade Admin · Accepted Answer

E=E° -(0.059/n)log10Q For Daniell cell, E° =1.10 V (equal to OA) E=1.10-(0.059/2)log0.01 =+1.159 V

Q. For Daniell cell,

$Z n (s) + C u^{2 +} (a q) ⇌ C u (s) + Z n^{2 +} (a q)$

The reaction quotient Q is given by

$Q = \frac{[ Z n ^{2 +} ]}{[ C u ^{2 +} ]}$

OA = 1.10 volt

Where $E_{ce ll} = 1.1591$ volt, then

Q = 0.01

Q = 100

Q = 0.1

Q = 1

$E = E^{\circ} - \frac{0.059}{n} l o g_{10} Q$

For Daniell cell, $E^{\circ} = 1.10$ V (equal to OA)

$E = 1.10 - \frac{0.059}{2} l o g 0.01$

$= + 1.159$ V

Q. For Daniell cell, Zn(s)+Cu2+(aq)⇌Cu(s)+Zn2+(aq) The reaction quotient Q is given by Q=[Cu2+][Zn2+]​ OA = 1.10 volt Where Ecell​=1.1591 volt, then