Question

For ${}^{\prime }{c}^{\prime }$ is an arbitrary constant, $\int e^{logx}dx=$

• A. $x/2+c$
• B. $e^{logx}+c$
• C. $x^2/2+c$
• D. $x+c$

Answer 1

Answer: (C)

We have,
$\int e^{logx}dx=\int xdx=\frac{x^2}{2}+c$