Question

The maximum number of electrons, present in an orbit that is represented by azimuthal quantum number $(l)=3$, will be

• A. $8$
• B. $2$
• C. $14$
• D. $6$

Answer 1

Answer: (C)

When azimuthal quantum number is $3$
$m=(21+1)$
$1=3$
$m=(2\times 3+1)$
$=7$ orbitals
then total values of $m=(2\times 3+1)=7$ orbitals.
We know that, one orbital contains two electrons.
Hence, total number of electrons $=7\times 2=14$.
Alternative
Total number of electrons $=4l+2$
$=4\times 3+2=12+2=14$ electrons