For a transparent medium relative permeability and permittivity, μ r and ϵr are 1.0 and 1.44 respectively. The velocity of light in this medium would be,

Question

For a transparent medium relative permeability and permittivity, μ r and ϵr are 1.0 and 1.44 respectively. The velocity of light in this medium would be, (A) 2.5 × 108 m/s (B) 3 × 108 m/s (C) 2.08 × 108 m/s (D) 4.32 × 108 m/s

Tardigrade Admin · Accepted Answer

v = (1/√μ ϵ) = (1/√μr ϵr μ0 ϵ0) = (3×108/√1.44) = (30/12) × 108 = 2.5 ×108 ms-1

Q. For a transparent medium relative permeability and permittivity, $μ_{r}$ and $ϵ_{r}$ are $1.0$ and $1.44$ respectively. The velocity of light in this medium would be,

2.5 × 10 $^{8}$ m/s

3 × 10 $^{8}$ m/s

2.08 × 10 $^{8}$ m/s

4.32 × 10 $^{8}$ m/s

$v = \frac{1}{μ ϵ}$
$= \frac{1}{μ _{r} ϵ _{r} μ _{0} ϵ _{0}}$
$= \frac{3 \times 1 0 ^{8}}{1.44}$
$= \frac{30}{12} \times 1 0^{8}$
$= 2.5 \times 1 0^{8} m s^{- 1}$

Q. For a transparent medium relative permeability and permittivity, μr​ and ϵr​ are 1.0 and 1.44 respectively. The velocity of light in this medium would be,

2.5 × 108 m/s

3 × 108 m/s

2.08 × 108 m/s

4.32 × 108 m/s