Question

For a series LCR circuit the power loss at resonance is :-

• A. $\frac{V^2}{[\omega L-\frac{1}{\omega C}]}$
• B. $I^{2}L\omega$
• C. $I^{2}R$
• D. $\frac{V^2}{C\omega }.$

Answer 1

Answer: (C)

In A.C. circuit power loss $P=VI\cos \varphi$
$P=VI=I^{2}R$ $(\because \varphi =0$ at resonance )