For a reaction to be spontaneous at all temperatures

Question

For a reaction to be spontaneous at all temperatures (A) Δ G and Δ H should be negative (B) Δ G for the reaction is zero (C) Δ G and Δ H should be positive (D) Δ G < Δ H

Tardigrade Admin · Accepted Answer

Δ G=Δ H-TΔ S For spontaneous reaction at all temperature Δ H=-ve Δ S=+ve So Δ G=-ve Δ G=Δ H-TΔ S For spontaneous reaction at all temperature Δ H=-ve Δ S=+ve So Δ G=-ve

Q. For a reaction to be spontaneous at all temperatures

$Δ G$ and $Δ H$ should be negative

$Δ G$ for the reaction is zero

$Δ G$ and $Δ H$ should be positive

$Δ G < Δ H$

$Δ G = Δ H - T Δ S$
For spontaneous reaction at all temperature
$Δ H = - v e$
$Δ S = + v e$
So $Δ G = - v e$
$Δ G = Δ H - T Δ S$
For spontaneous reaction at all temperature
$Δ H = - v e$
$Δ S = + v e$
So $Δ G = - v e$

Q. For a reaction to be spontaneous at all temperatures

ΔG and ΔH should be negative

ΔG for the reaction is zero

ΔG and ΔH should be positive

ΔG<ΔH

ΔG=ΔH−TΔS For spontaneous reaction at all temperature ΔH=−ve ΔS=+ve So ΔG=−ve ΔG=ΔH−TΔS For spontaneous reaction at all temperature ΔH=−ve ΔS=+ve So ΔG=−ve

$Δ G$ and $Δ H$ should be negative

$Δ G$ for the reaction is zero

$Δ G$ and $Δ H$ should be positive

$Δ G < Δ H$

$Δ G = Δ H - T Δ S$
For spontaneous reaction at all temperature
$Δ H = - v e$
$Δ S = + v e$
So $Δ G = - v e$
$Δ G = Δ H - T Δ S$
For spontaneous reaction at all temperature
$Δ H = - v e$
$Δ S = + v e$
So $Δ G = - v e$