For a reaction, the rate constant is expressed as, k = A.e-40000/T The energy of the activation is :

Question

For a reaction, the rate constant is expressed as, k = A.e-40000/T The energy of the activation is : (A) 40000 cal (B) 88000 cal (C) 80000 cal (D) 8000 cal

Tardigrade Admin · Accepted Answer

-(Ea/R)=-40000 Ea=40000×2=8×104 cal

Q. For a reaction, the rate constant is expressed as, $k = A . e^{- 40000/ T}$ The energy of the activation is :

40000 cal

88000 cal

80000 cal

8000 cal

$- \frac{E _{a}}{R} = - 40000$
$E_{a} = 40000 \times 2 = 8 \times 1 0^{4} c a l$

Q. For a reaction, the rate constant is expressed as, k=A.e−40000/T The energy of the activation is :

40000 cal

88000 cal

80000 cal

8000 cal

−REa​​=−40000 Ea​=40000×2=8×104cal

Q. For a reaction, the rate constant is expressed as, $k = A . e^{- 40000/ T}$ The energy of the activation is :

$- \frac{E _{a}}{R} = - 40000$
$E_{a} = 40000 \times 2 = 8 \times 1 0^{4} c a l$