For a reaction, P + Q → R + S. The value of Δ H° is -30 kJ mol-1 and Δ S is -100 J K-1 mol-1. At what temperature the reaction will be at equilibrium?

Question

For a reaction, P + Q → R + S. The value of Δ H° is -30 kJ mol-1 and Δ S is -100 J K-1 mol-1. At what temperature the reaction will be at equilibrium? (A) 27 °C (B) 52 °C (C) 30 °C (D) 45 °C

Tardigrade Admin · Accepted Answer

Δ G = Δ H - TΔ S, At equilibrium, Δ G = 0, Δ H = TΔ S 30000 = T × 100 T = 300 K or 27 °C

Q. For a reaction, $P + Q \to R + S$ . The value of $Δ H^{°}$ is $- 30 k J m o l^{- 1}$ and $Δ S$ is $- 100 J K^{- 1} m o l^{- 1}$ . At what temperature the reaction will be at equilibrium?

$27^{°} C$

$52^{°} C$

$30^{°} C$

$45^{°} C$

$Δ G = Δ H - T Δ S$ ,
At equilibrium, $Δ G = 0$ , $Δ H = T Δ S$
$30000 = T \times 100$
$T = 300 K$ or $27^{°} C$

Q. For a reaction, P+Q→R+S. The value of ΔH° is −30kJmol−1 and ΔS is −100JK−1mol−1. At what temperature the reaction will be at equilibrium?

27°C

52°C

30°C

45°C