For a reaction, I- + OCl-→ IO- +Cl- in an aqueous medium, the rate of reaction is given by (d[IO-]/dt)=k ([I-][OCl-]/[OH-]) The overall order of reaction is

Question

For a reaction, I- + OCl-→ IO- +Cl- in an aqueous medium, the rate of reaction is given by (d[IO-]/dt)=k ([I-][OCl-]/[OH-]) The overall order of reaction is (A) -1 (B) 0 (C) 1 (D) 2

Tardigrade Admin · Accepted Answer

(d[IO-]/dt)=k ([I-]1[OCl-]1/[OH-]1) Order of reaction =1 + 1 -1 = 1

Q. For a reaction, $I^{-} + OC l^{-} \to I O^{-} + C l^{-}$ in an aqueous medium, the rate of reaction is given by $\frac{d [ I O ^{-} ]}{d t} = k \frac{[ I ^{-} ] [ OC l ^{-} ]}{[ O H ^{-} ]}$ The overall order of reaction is

$- 1$

$0$

$1$

$2$

$\frac{d [ I O ^{-} ]}{d t} = k \frac{[ I ^{-} ] ^{1} [ OC l ^{-} ] ^{1}}{[ O H ^{-} ] ^{1}}$
Order of reaction $= 1 + 1 - 1 = 1$

Q. For a reaction, I−+OCl−→IO−+Cl− in an aqueous medium, the rate of reaction is given by dtd[IO−]​=k[OH−][I−][OCl−]​ The overall order of reaction is

−1

0

1

2

dtd[IO−]​=k[OH−]1[I−]1[OCl−]1​ Order of reaction =1+1−1=1

Q. For a reaction, $I^{-} + OC l^{-} \to I O^{-} + C l^{-}$ in an aqueous medium, the rate of reaction is given by $\frac{d [ I O ^{-} ]}{d t} = k \frac{[ I ^{-} ] [ OC l ^{-} ]}{[ O H ^{-} ]}$ The overall order of reaction is

$- 1$

$0$

$1$

$2$

$\frac{d [ I O ^{-} ]}{d t} = k \frac{[ I ^{-} ] ^{1} [ OC l ^{-} ] ^{1}}{[ O H ^{-} ] ^{1}}$
Order of reaction $= 1 + 1 - 1 = 1$