For a reaction, 2SO2(g) +O2(g) leftharpoons 2SO3(g), 1.5 moles of SO2 and 1 mole of O2 are taken in a 2 L vessel. At equilibrium the concentration of SO3 was found to be 0.35 mol L-1. The Kc for the reaction would be

Question

For a reaction, 2SO2(g) +O2(g) leftharpoons 2SO3(g), 1.5 moles of SO2 and 1 mole of O2 are taken in a 2 L vessel. At equilibrium the concentration of SO3 was found to be 0.35 mol L-1. The Kc for the reaction would be (A) 5.1 L mol-1 (B) 1.4 L mol-1 (C) 0.6 L mol-1 (D) 2.95 L mol-1

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/b8f9f7e102bddaa42c79688612eb6394-.png" /> Kc=((0.35)2/0.4×0.4×0.15) =5.1 textL mol-1

Q. For a reaction, $2 S O_{2 (g)} + O_{2 (g)} ⇌ 2 S O_{3 (g)}$ , $1.5$ moles of $S O_{2}$ and $1$ mole of $O_{2}$ are taken in a $2 L$ vessel. At equilibrium the concentration of $S O_{3}$ was found to be $0.35 m o l L^{- 1}$ . The $K_{c}$ for the reaction would be

$5.1 L m o l^{- 1}$

$1.4 L m o l^{- 1}$

$0.6 L m o l^{- 1}$

$2.95 L m o l^{- 1}$

$K_{c} = \frac{( 0.35 ) ^{2}}{0.4 \times 0.4 \times 0.15}$
$= 5.1 L mol^{- 1}$

Q. For a reaction, 2SO2(g)​+O2(g)​⇌2SO3(g)​, 1.5 moles of SO2​ and 1 mole of O2​ are taken in a 2L vessel. At equilibrium the concentration of SO3​ was found to be 0.35molL−1. The Kc​ for the reaction would be

5.1Lmol−1

1.4Lmol−1

0.6Lmol−1

2.95Lmol−1